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Question

Consider the following reduction processes:

Zn2++2eZn(s);Eo=0.76 V
Ca2++2eCa(s);Eo=2.87 V
Mg2++2eMg(s);Eo=2.36 V
Ni2++2eNi(s);Eo=0.25 V

The reducing power of the metals increases in the order:

A
Ca<Zn<Mg<Ni
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B
Ni<Zn<Mg<Ca
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C
Zn<Mg<Ni<Ca
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D
Ca<Mg<Zn<Ni
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Solution

The correct option is B Ni<Zn<Mg<Ca
Lower the reduction potential , higher is the tendency of the species to get oxidised and hence better will be reducing power. So, according to the given data correct order will be:
Ni<Zn<Mg<Ca

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