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Question

Consider the following reversible cycle shown below.

It operates a diatomic gas. It's efficiency is given as If its now replaced by a monatomic gas then the change in percentage efficiency of the cycle is η=γ1γP2P2P1+VV2V1

TakeP1=1 bar, P2=2 bar, v1=1m3, v2=2m3

A
4.77
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B
3.87
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C
2.35
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D
4.07
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Solution

The correct option is A 4.77
Efficiency with diatomic gas(γ=1.4)

η=1.411.4×2(21)+(121)=0.105=10.5%

Efficiency with monatomic gas(γ=1.06)

η=1.6611.66×2(21)+1(21)=0.1527=15.27%

ηη=15.2710.5=4.77%

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