Consider the following SDT-S- ABS-x -A-x- B-y-A-yA- aAA-x -A1-x-A-y-A1-yA- bA-x -A-B-y-a-1B- cB-x -c-B-y-c-1Above SDT is-

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Consider the ...

Question

Consider the following SDT.

$S \to A B {S . x = A . x; B . y = A . y}$
$A \to a A {A . x = A_{1} . x; A . y = A_{1} . y}$
$A \to b {A . x = A; B . y = a + 1}$
$B \to c {B . x = c; B . y = c + 1}$

Above SDT is______.

None of these

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S-attributed grammar only

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Both S-attributed & L-attributed grammar

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L-attributed grammar only

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Solution

The correct option is D L-attributed grammar only
x is synthesized attribute
y is depending on left sibling or child
So, given SDT is L-attributed.
It is not S-attributed grammar.

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$y = a e^{3 x} + b e^{- 2 x} .$

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Consider the following SDT. S→AB{S.x=A.x;B.y=A.y} A→aA{A.x=A1.x;A.y=A1.y} A→b{A.x=A;B.y=a+1} B→c{B.x=c;B.y=c+1} Above SDT is______.

The correct option is D L-attributed grammar onlyx is synthesized attribute y is depending on left sibling or child So, given SDT is L-attributed. It is not S-attributed grammar.

Consider the following SDT.

$S \to A B {S . x = A . x; B . y = A . y}$
$A \to a A {A . x = A_{1} . x; A . y = A_{1} . y}$
$A \to b {A . x = A; B . y = a + 1}$
$B \to c {B . x = c; B . y = c + 1}$

Above SDT is______.

The correct option is D L-attributed grammar only
x is synthesized attribute
y is depending on left sibling or child
So, given SDT is L-attributed.
It is not S-attributed grammar.