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Question

Consider the following sequence of reactions.


C2H5CCHCH3MgBr−−−−−−−−−−−−−A1.HCHO2.H3O+B
The product (B) is :

A
CH3CH2OH
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B
C2H5CCHCH2OH|CH3
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C
C2H5CCCHCH3|OH
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D
C2H5CCCH2OH
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Solution

The correct option is D C2H5CCCH2OH
The product B is C2H5CCCH2OH
C2H5CCHCH3MgBr−−−−−−−−−−−−−−−C2H5CC++MgBrA

C2H5CCA1.HCHO2.H3O+C2H5CCCH2OHB
Methyl magnesium bromide abstracts acidic H atom from 1-butyne. The anion thus formed attacks formaldehyde. Acid hydrolysis gives compound B.

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