Consider the following sequence of reactions.
The products $(A)$ and $(B)$ are :

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Solution

The correct option is A
In the first step nucleophilic addition occurs and a tetrahedral intermediate is formed which upon dehydration forms an oxime.

Hence a is the correct option.

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Similar questions

{C H}_{2} = {C H}_{2} c o l d - ------ \to d i l . {K M n O}_{4} A e x c e s s - --- \to {P C l}_{5} B

(A)

(B)

{C H}_{2} = {C H}_{2} c o l d - -------- \to d i l . K M n O_{4} A e x c e s s - --- \to P C I_{s} B

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