Consider the following series circuit shown in figure. For series resonance, the value of coupling coefficient, k will be
|XL|=|XC|
XC=−j12Ω
XL=j2+j8+j2M
XL=j10+j2k√16(M=k√L1L2)
XL=j10+j8k
j2=j10+j8k
j2=j8k
⇒k=28=0.25