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Nucleophilic Substitution in Alkyl Halides

Consider the ...

Question

Consider the following series of reactions:
$C l_{2} + 2 N a O H ⟶ N a C l + N a C l O + H_{2} O 3 N a C l O ⟶ 2 N a C l + N a C l O_{3} 4 N a C l O_{3} ⟶ N a C l + 3 N a C l O_{4}$

How many moles of $N a C l O_{3}$ obtained after the completion of reaction by taking 1 mole of $C l_{2}$ and other reagents in excess?

\frac{1}{3}

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0

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\frac{1}{4}

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1

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Solution

The correct option is B $0$
Given reactions are:
$C l_{2} + 2 N a O H ⟶ N a C l + N a C l O + H_{2} O 3 N a C l O ⟶ 2 N a C l + N a C l O_{3} 4 N a C l O_{3} ⟶ N a C l + 3 N a C l O_{4}$
$1$ mole of $C l_{2}$ reacts with $2$ moles of $N a O H$ to produce $1$ mole of $N a C l$ , $1$ mole of $N a C l O$ and $1$ mole of $H_{2} O$ .
But after the completion of reaction all the $N a C l O_{3}$ produced will decompose to give $N a C l$ and $N a C l O_{4}$ . Hence moles of $N a C l O_{3}$ obtained after the completion of reaction by taking 1 mole of $C l_{2}$ and other reagents in excess is zero.

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Similar questions

C l_{2} + 2 N a O H ⟶ N a C l + N a C l O + H_{2} O 3 N a C l O ⟶ 2 N a C l + N a C l O_{3} 4 N a C l O_{3} ⟶ N a C l + 3 N a C l O_{4}

N a C l

1

C l_{2}

C l_{2} + 2 N a O H \to N a C l + N a C l O + H_{2} O

3 N a C l O \to 2 N a C l + N a C l O_{3}

4 N a C l O_{3} \to 3 N a C l O_{4} + N a C l

C l_{2}

106.5

N a C l O_{3}

I) C l_{2} + 2 N a O H \to N a C l + N a C l O + H_{2} O

I I) 3 N a C l O \to 2 N a C l + N a C l O_{3}

I I I) 4 N a C l O_{3} \to 3 N a C l O_{4} + N a C l

C l_{2}

N a C l O_{4}

I) C l_{2} + 2 N a O H \to N a C l + N a C l O + H_{2} O

I I) 3 N a C l O \to 2 N a C l + N a C l O_{3}

I I I) 4 N a C l O_{3} \to 3 N a C l O_{4} + N a C l

C l_{2}

N a C l O_{4}

N a O C l Δ \to N a C l O_{3} + N a C l

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