Question

Consider the following sets of quantum numbers.

(i) n - 3, l - 0, m - 0, s - +1/2

(ii) n - 2, l - 2, m - 1, s - +1/2

(iii) n - 4, l - 3, m - 2, s -1/2

(iv) n - 1, l - 0, m - 1, s -1/2

(v) n - 3, l - 2, m - 3, s - +1/2

Which of the following sets of quantum numbers is not possible?

• A. (ii) , (iii) and (iv)
• B. (i), (ii) , (iii) and (iv)
• C. (ii) , (iv) and (v)
• D. (i) and (iii)

Answer 1

The correct option is C (ii) , (iv) and (v)

(i) $n=3l=0,m=0s=\frac{+1}{2}$

(ii) $3sn>l$

$n\ne l$

So, not possible.

(iii) $4f$ possible.

(iv) Not possible

For $s,m=0$(always)

(v) not possible

$l=2$ i.e $d$ cannot have $m=-3$

$m$ for $d$ is $-l$ to $+l$ i.e $-2$ to $+2$

So, the correct option is $C$