Consider the following species: $N^{3 -}, O^{2 -}, F^{-}, N a^{+}, M g^{2 +} a n d A l^{3 +}$
(a)What is common in them?
(b)Arrange them in the order of increasing ionic radii.

Open in App

Solution

(a) Each of the given species (ions) has the same number of electrons (10 electrons). Hence, the given species are isoelectronic.

(b)The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge. The arrangement of the given species in order of their increasing nuclear charge is as follows: $N^{3 -} < O^{2 -} < F^{-} < N a^{+} < M g^{2 +} < A l^{3 +}$
Nuclear charge = +7 +8 +9 +11 +12 +13
Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:
$A l^{3 +} < M g^{2 +} < N a^{+} < F^{-} < O^{2 -} < N^{3 -}$

Suggest Corrections

136

Similar questions

{M g}^{2 +}, O^{2 -} {A l}^{3 +}; N^{3 -}, F^{-}, {N a}^{+}

N^{3 -}, O^{2 -}, M g^{2 +}

F^{-}

Consider the following species:

N^3–, O^2–, F^–, Na⁺, Mg²⁺ and Al³⁺

(a) What is common in them?

(b) Arrange them in the order of increasing ionic radii.

N a^{+}, M G^{2 +}, O^{2 -}, F^{-} A l^{3 +}, N^{3 -}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program