Consider the following statements and arrange in the order of true/false as given in the codes. S1:Na2O2<MgO<ZnO<P4O10: Acidic property. S2:Na<Mg>Al<Si: First ionisation energy. S3:F>Cl>Br: Electron affinity.
A
TTT
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B
TFF
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C
TTF
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D
TFT
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Solution
The correct option is C TTF S1:Na2O2<MgO<ZnO<P4O10: as non-metallic character increases the acidic character increases. MgO,Na2O are basic, ZnO amphoteric and P4O10 acidic. S2:Na<Mg>Al<Si, Mg has higher first ionisation energy than Na due to small size and high electron penetration power of s-subshell electrons) and Si has higher ionization energy than AlandMg because of higher nuclear charge and small size. IE1:Na=496,Al=577,Mg=737andSi=786kJ/mole S3: There is more inter-electronic repulsion in 2p-subshell of fluorine than chlorine (3p). So extra electron will be added easily in 3p-subshell of chlorine as compared to 2p-subshell of fluorine.. Down the group electron affinity values generally decrease with increase in atomic number due to increase in atomic size. So Cl>F>Br.