Question

Consider the following statements and arrange in the order of true/ false as given in the codes.
$S_1$: The IUPAC name of the compound $\left[Cr\right(N{H}_3{)}_5\left(NCS\right)\left]\right[ZnC{l}_4]$ is pentaamminethiocyanato-N-chromate(III) tetrachlorozincate (II).
$S_2:CoS{O}_4$ is paramagnetic and coloured.
$S_3:\left[Co\right(N{H}_3{)}_4\left(N{O}_2{)}_2\right]N{O}_3$ shows ionisation, linkage and geometrical isomerism.
$S_4$: The C-O bond length in the complex, $\left[Fe\right(CO{)}_5]$ is same as that found in carbon monoxide itself.

• A. F T T T
• B. T T T T
• C. F T T F
• D. T T T F

Answer 1

The correct option is C F T T F

$CoS{O}_4,$ with $Co\left(II\right)$ ion having $\left[Ar\right]3d^{7}4s^o$ outer electronic configuraton contains two unpaired electrons and is paramagnetic and colored.
The ionization isomers are $Co\left(N{H}_3{)}_4\right(N{O}_2{)}_2]N{O}_3$ and $\left[Co\right(N{H}_3{)}_4\left(N{O}_3\right)]N{O}_2$
Linkage isomers are $\left[Co\right(N{H}_3{)}_4\left(N{O}_2{)}_2\right]N{O}_3$ and $\left[Co\right(N{H}_3{)}_4\left(N{O}_2\right)\left(ONO\right)]N{O}_3$
cis and trans isomers are the geometrical isomers. Total 10 isomers are possible for this compound.
Hence both statements are true.
The IUPAC name of $Cr\left(N{H}_3{)}_5\right(NCS\left)\right]\left[ZnC{l}_4\right]$ is pentaamminethiocyanato-N-chromium(III) tetrachlorozincate (II). or
pentaammineisothiocyanatochromium(III) tetrachlorozincate (II).
In metal carbonyls, due to synergic bonding between metal and ligand, the bond between $C$ and $O$ becomes weak. Hence, the bond length increases.
Hence, both statements are incorrect.