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Question

Consider the following statements and arrange in the order of true/false as given in the codes.
S1: When copper sulphate is added to K2[Hgl4] solution and SO2 is passed into this solution, white precipitate is obtained.
S2: When copper sulphate solution is boiled with glucose in presence of caustic soda, a blue precipitate is obtained.
S3: Pure Cu2Cl2 is white, but moist air converts it in to a dark blue material.

A
TTT
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B
TFT
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C
FFF
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D
FTF
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Solution

The correct option is C FFF
S1: False. When Copper sulphate is added to K2HgI4 and SO2 is passed the solution a scarlet red precipitate of Cu2[HgI4] is formed.
H2O+K2Hgl4+2CuSO4+SO2Cu2[Hgl4](red color)+K2SO4+2H2SO4
S2: False.When copper sulphate solution is boiled with glucose in presence of caustic soda, a red precipitate of cuprous oxide is formed. Copper Sulphate reacts with caustic soda and forms blue solution of copper hydroxide. When this solution is treated with glucose , a red precipitate of Cu2O is formed.
CuSO4+2NaOHCu(OH)2(blue color)+Na2SO4
2Cu(OH)2+CH2OH(CHOH)4CHOCu2O(red color)+H2O+CH2OH(CHOH)4COOH
S3: False. Pure Cu2Cl2 is white in color, but moist air converts it into a dark green material. The pure compound is stable is dry air, moist air convert it to greenish oxygenated compound and upon exposure to light it is transformed to copper (II) chloride.
Cu2Cl2CuCl2.3Cu(OH)2(dark green color)

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