Consider the following statements and arrange in the order of true/false as given in the codes.
$S_{1}$ : When copper sulphate is added to $K_{2} [H g l_{4}]$ solution and $S O_{2}$ is passed into this solution, white precipitate is obtained.
$S_{2}$ : When copper sulphate solution is boiled with glucose in presence of caustic soda, a blue precipitate is obtained.
$S_{3}$ : Pure $C u_{2} C l_{2}$ is white, but moist air converts it in to a dark blue material.

TTT

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FFF

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Solution

The correct option is C FFF
$S_{1}$ : False. When Copper sulphate is added to $K_{2} H g I_{4}$ and $S O_{2}$ is passed the solution a scarlet red precipitate of $C u_{2} [H g I_{4}]$ is formed.
$H_{2} O + K_{2} H g l_{4} + 2 C u S O_{4} + S O_{2} \to C u_{2} [H g l_{4}] ↓ (red color) + K_{2} S O_{4} + 2 H_{2} S O_{4}$
S2: False.When copper sulphate solution is boiled with glucose in presence of caustic soda, a red precipitate of cuprous oxide is formed. Copper Sulphate reacts with caustic soda and forms blue solution of copper hydroxide. When this solution is treated with glucose , a red precipitate of $C u_{2} O$ is formed.
$C u S O_{4} + 2 N a O H C u (O H)_{2} ↓ (blue color) + N a_{2} S O_{4}$
$2 C u (O H)_{2} + C H_{2} O H (C H O H)_{4} C H O \to C u_{2} O ↓ (red color) + H_{2} O + C H_{2} O H (C H O H)_{4} C O O H$
S3: False. Pure $C u_{2} C l_{2}$ is white in color, but moist air converts it into a dark green material. The pure compound is stable is dry air, moist air convert it to greenish oxygenated compound and upon exposure to light it is transformed to copper (II) chloride.
$C u_{2} C l_{2} \to C u C l_{2} .3 C u (O H)_{2} (dark green color)$

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