Question

Consider the following statements and arrange in the order of true/false as given in the codes.
$S_1$; The hydrogen bond in salt, $KH{F}_2$ is stronger than in gaseous HF.
$S_2$; The dipole moment of $C{H}_{3}F$ is greater than that of $C{H}_{3}Cl$
$S_3$ ; $s{p}^2$ hybrid orbitals have equal s and p character .
$S_4$; Two types of bonds presnt in $B_2{H}_6$ are covalent and three centre-two electron bond

• A. T T F F
• B. T F F T
• C. F F F T
• D. F F T T

Answer 1

The correct option is C F F F T

$S_1:KH{F}_2,F-H-F;\Delta H\approx -212kJmo{l}^{-1},\text{involves resonance}H-F-H\leftrightarrow H-F-H.$

$HF,F-H-F;\Delta H\approx -28.6kJmo{l}^{-1}$

$S_2:C{H}_{3}Cl>C{H}_{3}F\text{due to large charge separation in}C{H}_{3}Cl\text{as compared to that in}C{H}_{3}F.$

$C{H}_{3}F;\mu =1.85D,C{H}_{3}Cl;\mu =1.87D$

$S_3;\text{In}s{p}^2\text{hybrid orbital s character is}33.3\%\text{and p character is}66.6\%$

$S_4:\text{Terminal B−H bond is covalent while bridging B−H bonds are three centre - two-electron bonds.}$

Option C is correct.