wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the following statements and select the correct code.
1. For a given stress, the strain produced in glass is much less than that in rubber.
2. In plastic materials, the force of cohesion are very small.
3. Elastic limit is the smallest stress which results in permanent distortion.

A
1, 2 and 3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1 and 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 and 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 and 3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1, 2 and 3
1. Rubber has lower Elasticity modulus so strain is higher in rubber compared to glass.
2. In plastic, which is polymer, inter-molecular forces are very small.
3. If stress is applied beyond the Elastic limit, material suffers permanant distortion.

All statements are correct.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hardness
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon