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Byju's Answer
Standard XI
Mathematics
Algebra of Complex Numbers
Consider the ...
Question
C
o
n
s
i
d
e
r
t
h
e
f
o
l
l
o
w
i
n
g
s
t
a
t
e
m
e
n
t
s
:
F
00
(
0
)
−
1
,
F
00
(
1
)
=
1
F
00
(
n
)
=
10
×
F
00
(
n
−
1
)
+
100
×
F
00
(
n
−
2
)
f
o
r
n
≥
2
T
h
e
n
w
h
a
t
w
i
l
l
b
e
t
h
e
v
a
l
u
e
o
f
F
00
(
3
)
?
A
1200
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B
1
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C
600
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D
110
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Solution
The correct option is
A
1200
F
00
(
0
)
=
1
,
F
00
(
1
)
=
1
F
00
(
n
)
=
10
×
F
00
(
n
−
1
)
+
100
F
00
(
n
−
2
)
,
i
f
n
≥
2
F
00
(
2
)
=
10
×
F
00
(
1
)
+
100
F
00
(
0
)
=
(
10
×
1
)
+
(
100
×
1
)
=
10
+
100
=
110
S
i
m
i
l
a
r
l
y
:
F
00
(
3
)
=
10
×
F
00
(
2
)
+
100
F
00
(
1
)
=
(
10
×
110
)
+
(
100
×
1
)
=
1100
+
100
=
1200
Suggest Corrections
0
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