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Question

Consider the following statements.
I. In SiMe2Cl2, ClSiCl is smaller than MeSiMe.
II. MeOMe of Me2O is smaller than FOF of F2O.
III. CCl bond length of CH3Cl is shorter than CCl bond length of CF3Cl.
IV. CF bond length of CH3F is greater than CF bond length of CH2F2.

A
TFTF
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B
TFFT
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C
FTTF
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D
FTFT
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Solution

The correct option is B TFFT
According to the Bent's rule, more electronegative atom occupies orbital having less s character.
I. In SiMe2Cl2, SiCl bond has more p character which results in lesser bond angle than SiMe bond having more s charater.
II. Bent' rule suggests that a hybrid orbital having more s character will be oriented toward less electropositive lone pair whereas orbital having more p character will be directed toward more electronegative F atom in F2O. Hence, F2O has larger bond angle.
III. CCl bond of CH3Cl has more p character than CCl bond of CF3Cl according to Bent's rule. Hence the former bond is longer than later.
IV. CF bond of CH3F has more p character than CF bond of CH2F2 since in the later, p character is shared by two F atoms. Hence former bond length is longer than the later.

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