I is true,
for example take L={an bn d}∪{an b2n d}.
It's reversal will be [Can bn] L {dan b2n] which is a DCFL. So, I is okay.
II is also true. lets take L={an|p is prime} If we take its kleene closure .
Then Ln=ϵ−aaa∗
Hence II is also correct.
Therefore (a) is the most appropriate choice