The correct option is D Ionic product of water is temperature dependent.
The explanation (I),
millimoles of H+=400×0.1×2=80
Millimoles of OH−=400×0.1×2=40
(Limiting reagent)
∴ Millimoles of H+ left =80−40=40
[H+]=40400+400=40800=120 M
⟹ pH=− log[H+]=− log(120)
=− log 1 + log 2 +log 10
=− 0 + 0.301 + 1
⟹1.30
Hence, the statement I is correct.
In statement II, the ionic product of H2O is temperature dependent.
Kw=[H+][OH−]=10−14(mol/L)2 at 25o C
With increase in temperature, dissociation of H2O units into H+ and OH− ions will also increase. As a result, the value of ionic product, [H+]×[OH−] will be increased.
Hence, the statement II is correct.
In statement III, for a weak monobasic acid HA,
HA(1−α) C M⇌Hα C M++Aα C M−
⟹ pH of the solution is,
[H+]=10−5 M=αC
⟹Ka=αC×αC(1−α)C=10−5×α1−C
⟹10−5=10−5×α1−α
⟹α=0.5
⟹α%=50
In statement IV, Le- Chatelier's principle is applicable to common ion effect. Because, in presence of common ion (given) by strong electrolyte (say, Na+A−), the product of the concentration terms in RHS increases. For the weaker electrolyte, HA (say) the equilibrium shifts to the LHS,
HA⇌H++A−
As a result dissociation of HA gets supressed. Hence, the statement IV is incorrect.