Question

Consider the following Sum of products expression, F.

F = $ABC+\overline{A}\overline{B}C+A\overline{B}C+\overline{A}BC+\overline{A}\overline{B}\overline{C}$
The equivalent product of Sums expression is

• A. F = $(\overline{A}+B+\overline{C})+(A+\overline{B}+\overline{C})+(A+B+C)$
• B. F = $(A+\overline{B}+C)+(\overline{A}+B+C)+(\overline{A}+\overline{B}+C)$
• C. F = $(A+\overline{B}+\overline{C})+(A+B+C)+(\overline{A}+\overline{B}+\overline{C})$
• D. F = $(\overline{A}+\overline{B}+C)+(A+B+\overline{C})+(A+B+C)$
  

Answer 1

The correct option is B F = $(A+\overline{B}+C)+(\overline{A}+B+C)+(\overline{A}+\overline{B}+C)$

The SOP form of F is (shown in K-map)

So, POS forms can be formed using '0' from the K-map.
POS = $(\overline{A}+B+C)(\overline{A}+\overline{B}+C)(A+\overline{B}+C)$