Consider the following systems-System 1- Gs-12s-1System 2- Gs-15s-1The true statement regarding the system is

T(s)=C[s| A]^ 1b+d System 1: G(s)=1(2s+1) Time constant τ_1=2sec System 2: G(s)=1(5s+1) nbsp; Time constant τ_2=5sec. Bandwidth is inversely proportional ...

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Control Systems

Frequency Domain Specifications-2

Consider the ...

Question

Consider the following systems:

$S y s t e m 1 : G (s) = \frac{1}{(2 s + 1)}$

$S y s t e m 2 : G (s) = \frac{1}{(5 s + 1)}$

The true statement regarding the system is

Bandwidth of system 1 is greater then the bandwidth of system 2

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Bandwidth of system 1 is lower than the handwidth of system 2

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Bandwidth of both the systems are the same

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Bandwidth of both the systems are infinite

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Solution

The correct option is A Bandwidth of system 1 is greater then the bandwidth of system 2
$T (s) = C [s | - A]^{- 1} b + d$

$S y s t e m 1 : G (s) = \frac{1}{(2 s + 1)}$
$T i m e - c o n s t a n t τ_{1} = 2 s e c$

$S y s t e m 2 : G (s) = \frac{1}{(5 s + 1)}$
$T i m e c o n s t a n t τ_{2} = 5 s e c .$

Bandwidth is inversely proportional to time constant.

$F o r s y s t e m 1 \Rightarrow B W_{1} \infty \frac{1}{2}$
$F o r s y s t e m 2 \Rightarrow B W_{2} \infty \frac{1}{5}$

Hence, system 1 is having more bandwidth compared to system 2.

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Consider the following systems: System1:G(s)=1(2s+1) System2:G(s)=1(5s+1) The true statement regarding the system is

Consider the following systems:

$S y s t e m 1 : G (s) = \frac{1}{(2 s + 1)}$

$S y s t e m 2 : G (s) = \frac{1}{(5 s + 1)}$

The true statement regarding the system is