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Question

Consider the following transformations of a compound P.

Choose the correct options.


  1. X is Pd-C/quinoline/H2

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Solution

The correct option is C

Explanation for the correct options:

B X is Pd-C/quinoline/H2

  1. Compound P given in question reacts in presence of H2/Pt to form 1-propane cyclohexane.
  2. We know that alkynes react with H2/Pt to form alkanes hence compound P is an alkyne.
  3. Now forX: When alkynes react with Pd-C/quinoline/H2 (lindlar's catalyst) then alkenes are formed, as given in the question.

C

  1. As we know that the product formed in the reaction, of compound P with H2/Pt is 1-propane cyclohexane.
  2. We also know that compounds X react with alkynes to form alkene.
  3. From the above two reactions, we can estimate that product P is 1-ethyne cyclohex-2-ene.

Explanation for the incorrect option:

A

  1. As we know that the product formed in the reaction, of compound P with H2/Pt is 1-propane cyclohexane.
  2. We also know that compound X react with alkynes to form alkene.
  3. From the above two reactions, we can estimate that product P is 1-ethyne cyclohex-2-ene.
  4. Hence option A is incorrect.

D

  1. As we know that product P is 1-ethyne cyclohex-2-ene.
  2. So when 1-ethyne cyclohex-2-ene react with NaNH2 in presence of acid undergo elimination reaction to form optically active compounds.
  3. The compound given in option D is not possible to accept because there is the presence of triple and double bonds in continuity, which is not possible.
  4. Hence option D is incorrect.

Hence options B and C are correct, X is Pd-C/quinoline/H2 and product P is 1-ethyne cyclohex-2-ene.


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