Question

Consider the following unbalanced reactions.$C{l}_2\left(g\right)+Ba\left(O{H}_2\right)\to X\left(aq\right)+BaC{l}_2+H_{2}O$
$X+H_{2}S{O}_4\to Y+BaS{O}_4$
$Y\underset{>365K}{\overset{\Delta }{\to }}Z+H_{2}O+O_2$ Here, $Y$ and $Z$ are respectively :

• A. $HCl{O}_4,Cl{O}_2$
• B. $HCl{O}_3,Cl{O}_2$
• C. $HCl{O}_3,C{l}_2{O}_7$
• D. $HCl{O}_4,C{l}_2{O}_7$

Answer 1

Answer: (B)

$HCl{O}_3,Cl{O}_2$

The complete reaction sequence is as follows:
$7C{l}_2\left(g\right)+6Ba(OH{)}_2\to 2Ba(Cl{O}_3{)}_2+4BaC{l}_2+6H_{2}O$
$Ba(Cl{O}_3{)}_2+H_{2}S{O}_4\to 2HCl{O}_3+BaS{O}_4$
$2HCl{O}_3\underset{\Delta >365K}{\overset{\Delta }{\to }}2Cl{O}_2+H_{2}O+\frac{1}{2}{O}_2$

Hence, $Y$ and $Z$ are $HCl{O}_3$ and $Cl{O}_2$ respectively.