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Question

Consider the following unit values of energy :


I. 1 L atm II. 1 erg
III. 1 J IV. kcal

Increasing the order of these values is :

A
I=II=III=IV
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B
I<II<III<IV
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C
II<III<I<IV
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D
IV<I<III<III
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Solution

The correct option is C II<III<I<IV
R=0.0821 L atm mol1K1

R=8.314×107ergs mol1K1

R=8.314 J mol1K1

R=0.002 kcal mol1K1

1L atm=R0.0821molK

1 erg=R8.314×107molK

1 J=R8.314mol K

1 kcal=R0.002mol K

Thus, II<III<I<IV

Hence, the correct option is C.

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