wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the four wooden blocks shown below.


FA is the force exerted on block A to move it from rest.
FB is the force exerted on block B to keep it moving with a constant speed of 5 m/s.
FC is the force exerted on block C to move it from rest.
FD is the force exerted on block D to move it from rest.

Select the correct statement.

A
FA is maximum.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
FB is maximum.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
FA is equal to FC.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
FD is maximum.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A FA is maximum.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work done by the force of gravity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon