Question

Consider the frame shown below



If then distribution factor for member BC is ____
$I_{AB}:I_{BC}:I_{CD}=1:2:1$

• A. 0.765

Answer 1

The correct option is A 0.765

Joint	Member	Relative stiffness	Total relative stiffness	Distribution factor
	BA	$\frac{I}{6.5}$	$\frac{17I}{26}$	$\frac{4}{17}$
B	BC	$\frac{2I}{4}$	$\frac{13}{17}=0.765$