Consider the frequency distribution of the heights of 60 students of a class:

$\begin{matrix} H e i g h t (i n c m) & N o . o f . S t u d e n t s & C u m u l a t i v e F r e q u e n c y 150 - 155 & 16 & 16 155 - 160 & 12 & 28 160 - 165 & 9 & 37 165 - 170 & 7 & 44 170 - 175 & 10 & 54 175 - 180 & 6 & 60 \end{matrix}$

The sum of the lower limit of the modal class and the upper limit of the median class is :

(a) 310 (b) 315 (c) 320 (d) 330

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Solution

Modal class = 150-155
So, lower limit of modal class is 150.
Total (n) = 60
$\frac{n}{2}$ = 30
Median class = 160-165
So, upper limit of median class = 165
Sum of the lower limit of the modal class and upper limit of the median class = 150 + 165 = 315
Hence, correct option is (b).

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