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Byju's Answer
Standard XII
Mathematics
Existence of Limit
Consider the ...
Question
Consider the function
√
(
1
+
x
)
−
√
(
1
−
x
)
x
Find the limit as
x
→
0.
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Solution
Required limit is,
=
lim
x
→
0
√
(
1
+
x
)
−
√
(
1
−
x
)
x
=
lim
x
→
0
√
(
1
+
x
)
−
√
(
1
−
x
)
x
.
√
(
1
+
x
)
+
√
(
1
−
x
)
√
(
1
+
x
)
+
√
(
1
−
x
)
=
lim
x
→
0
(
1
+
x
)
−
(
1
−
x
)
x
[
√
(
1
+
x
)
+
√
(
1
−
x
)
]
=
lim
x
→
0
2
√
(
1
+
x
)
+
√
(
1
−
x
)
=
2
1
+
1
=
1
.
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