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Question

Consider the given chemical equation
2PbS+3O22PbO+2SO2
The process is

A

roasting
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B

calcination
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C

smelting
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D

thermite process
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Solution

The correct option is A
roasting
It is easier to obtain lead (Pb) from its oxide, as compared to its sulphide. Therefore, prior to reduction, PbS (sulphide ore) is converted into lead oxide (PbO) by heating strongly in the presence of excess air. This process is known as roasting.

2PbS+3O22PbO+2SO2

Hence, the correct answer is option (a).

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