The correct option is D CH3COONa and CH3COOH
Ethanoic acid (CH3COOH) reacts with sodium carbonate (Na2CO3) and sodium hydrogen carbonate (NaHCO3) to give rise to sodium acetate (CH3COONa), carbon dioxide (CO2) and water (H2O).
2CH3COOH+Na2CO3→2CH3COONa+CO2+H2O
′W′ ′Y′
CH3COOH+NaHCO3→CH3COONa+CO2+H2O
′W′ ′Y′
Hence, the correct answer is option (d).