Consider the homogeneous gaseous equilibrium A-B -8652-X-Y- if the initial -A-B-2-00 M and the equilibrium -X-1 M- then the value of KC is

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Standard XII

Chemistry

Effect of Catalyst

Consider the ...

Question

Consider the homogeneous gaseous equilibrium $A + B ⇌ X + Y$ ; if the initial [A]=[B]=2.00 M and the equilibrium [X]=1 M, then the value of $K_{C}$ is

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Dear Student,

$A + B \leftrightarrow X + Y Initial 2 2 0 0 Equil . 2 - x 2 - x x x It is given that, x = 1 M So, [A] = [B] = 2 - x = 2 - 1 = 1 M and, [X] = [Y] = 1 M Hence, K_{c} = \frac{[X] [Y]}{[A] [B]} = \frac{(1) (1)}{(1) (1)} = 1$

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Consider the homogeneous gaseous equilibrium A+B⇌X+Y; if the initial [A]=[B]=2.00 M and the equilibrium [X]=1 M, then the value of KC is

Dear Student, A + B ↔ X + YInitial 2 2 0 0Equil. 2-x 2-x x xIt is given that, x=1 MSo, [A]=[B]=2-x=2-1=1 Mand, [X]=[Y]=1 MHence, Kc =[X][Y][A][B] =(1)(1)(1)(1) =1

Consider the homogeneous gaseous equilibrium $A + B ⇌ X + Y$ ; if the initial [A]=[B]=2.00 M and the equilibrium [X]=1 M, then the value of $K_{C}$ is

Dear Student,

$A + B \leftrightarrow X + Y Initial 2 2 0 0 Equil . 2 - x 2 - x x x It is given that, x = 1 M So, [A] = [B] = 2 - x = 2 - 1 = 1 M and, [X] = [Y] = 1 M Hence, K_{c} = \frac{[X] [Y]}{[A] [B]} = \frac{(1) (1)}{(1) (1)} = 1$