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Question

Consider the integral I=π0ln(sinx)dx.What is π20 ln (sinx)dx equal to?

A
4I
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B
2I
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C
I
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D
I2
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Solution

The correct option is D I2
I=π0ln(sinx)dx
using property,
I=π20(ln(sin(2πx)+ln(sinx))dx

we know that sin(x)=sin(2πx)

I=2π20ln(sinx)dx

I2=π20ln(sinx)dx

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