Question

Consider the junction diode as ideal. The value of current flowing through $AB$ is

• A. $0A$
• B. ${10}^{-2}A$
• C. ${10}^{-1}A$
• D. ${10}^{-3}A$

Answer 1

The correct option is B ${10}^{-2}A$

For ideal diode there is no voltage drop across diode. Let I be the current flowing through AB to the right.

Here, $V_A-V_B=IR$ or $4-(-6)=1000I$

or $I={10}^{-2}A$