Consider the lines represented by the equation (x2+xy−x)(x−y)=0, forming a triangle, then
Column1Column2(a)Orthocentre of traingle(16,12)(b)Circumcenter(12+2√2)(c)Centroid(0,12)(d)Incenter(12,12)
a-s, b-r, c-p, d-q
Given lines are (x2+xy−x)(x−y)=0
x(x+y-1)(x-y)=0
or x=0, x+y-1=0 and x-y=0 forms triangle OAB as shown in the diagram.