m(t)=2[u(t)−(t−1)u(t−1)−(t−3)u(t−3)u(t−3)+(t−4)u(t−4)]
t∫−∞m(t)dt=[tu(t)−(t−1)2u(t−1)−(t−3)2u(t−3)+(t−4)2u(t−4)]
By plotting t∫−∞m(t)dt, we get,
So,∣∣∣t∫−∞m(t)dt∣∣∣=6
Δϕmax=2π(0.5)(6)=6πrad=18.85rad