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Question

Consider the nuclear change-

Np93237-αA-βBαC

Which of the following statements is not correct?


  1. Mass number of B is 233

  2. Atomic number of A is 91.

  3. C is an isotope of A.

  4. B is an isobar of A.

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Solution

The correct option is C

C is an isotope of A.


Step 1: Introduction

The nuclear reaction is the reaction where unstable nuclei can split into smaller stable nuclei and emits alpha, beta and gamma particles.

Alpha particle is represented as He24 and beta particle is represented as e-10.

Step 2: Determining A, B and C.

When alpha particle emits from the Np then A element is produce.

Np93237-H24eA91233

So, the atomic number of A is 91. Hence, option B is correct

When beta particle emits from the A then B element is produce.

Np93237-H24eA91233-e-10B92233

So, the mass number of B is 233. Hence, option A is correct.

B is the isobar of A because they have the same mass number but a different atomic number. Hence, option D is also correct.

Np93237-H24eA91233-e-10B92233-H24eC90229

C is not an isotope of A because they do not have the same atomic number.

Final answer:

Hence, option C is correct.


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