Question

Consider the nuclear fission ${\text{Ne}}^{20}\to 2{\text{He}}^{+}+{\text{C}}^{12}$.
Given that the binding energy/nucleon of ${\text{Ne}}^{20},{\text{He}}^{+}{\text{and C}}^{12}$ are $8.03\text{MeV},7.07\text{MeV and}7.86\text{MeV}$ respectively. Identify the correct statement

• A. Energy of $12.4\text{MeV}$ will be supplied
• B. $8.3\text{MeV}$ energy will be released
• C. Energy of $3.6\text{MeV}$ will be released
• D. Energy of $9.72\text{MeV}$ has to be supplied

Answer 1

The correct option is D Energy of $9.72\text{MeV}$ has to be supplied

${\text{Ne}}^{20}\to 2{\text{He}}^{+}+{\text{C}}^{12}$

Let energy supplied be $E_B$
$E_B+8.03\times 20\to 2\times 7.07\times 4+7.86\times 12$

$\therefore E_B=(BE{)}_{react}-(BE{)}_{product}=9.72\text{MeV}$

Option d is best possible answer