Question

Consider the nuclear reaction: X${}^{200}$ $\to$A ${}^{110}$+B${}^{90}$+ energy .
The binding energy per nucleon for X ${}^{200}$, A ${}^{110}$, B${}^{90}$ is respectively 7.4MeV, 8.2MeV and 8.2Mev. The energy released is

• A. 200MeV
• B. 160MeV
• C. 110MeV
• D. 90MeV

Answer 1

The correct option is B 160MeV

${}^{200}X{\to }^{110}A{+}^{90}B+Q$

$\therefore Q=BE{)}_A+BE{)}_B-BE{)}_X$
$\Rightarrow Q=100\times 8.2+90\times 8.2-200\times 7.9$
$\Rightarrow Q=160MeV$