Question

Consider the nuclear reaction $X^{200}\to A^{110}+B^{90}$ If the binding energy per nucleon for X, A and B is $7.4\text{MeV}$, $8.2\text{MeV}$ and $8.2\text{MeV}$ respectively, what is the energy released?

• A. $200\text{MeV}$
• B. $160\text{MeV}$
• C. $110\text{MeV}$
• D. $90\text{MeV}$

Answer 1

The correct option is B $160\text{MeV}$

Energy released = BE of Products – BE of Reactants
$(8.2\times 110+8.2\times 90)-7.4\times 200$
$=160\text{MeV}$