Question

Consider the number $126+x,$ where $x$ is a single-digit number. Find the value(s) of $x$ such that the given number is divisible by $4.$

• A. $2$
• B. $-2$
• C. $4$
• D. $6$

Answer 1

Answer: (A), (B), (D)

$6$

For a number to be divisible by $4,$ the last two digits should be divisible by $4.$

At $x=2$
$\Rightarrow 126+x=126+2=128$
which is divisible by 4.

At $x=-2$
$\Rightarrow 126+x=126+(-2)=124$ which is divisible by 4.

At $x=4$
$\Rightarrow 126+x=126+4=130$ which is not divisible by 4.

At $x=6$
$\Rightarrow 126+x=126+6=132$ which is divisible by 4.