Consider the number $146 + x,$ where $x$ is a single-digit number. Find the value(s) of $x$ such that the given number is divisible by $4.$

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6$
For a number to be divisible by $4,$ the last two digits should be divisible by $4.$

At $x = 2$
$\Rightarrow 146 + x = 146 + 2 = 148$
which is divisible by 4.

At $x = - 2$
$\Rightarrow 146 + x = 146 + (- 2) = 144$ which is divisible by 4.

At $x = 4$
$\Rightarrow 146 + x = 146 + 4 = 150$ which is not divisible by 4.

At $x = 6$
$\Rightarrow 146 + x = 146 + 6 = 152$ which is divisible by 4.

Suggest Corrections

Similar questions

x

18 x 71

3

x

\bar{66784 x}

x

y

tan x + tan y = 42

cot x + cot y = 49

tan (x + y)

If $98215 x 2$ is a number with $^{'} x^{'}$ as its tens digit such that it is divisible by $4.$ Find all possible values of $^{'} x^{'}$

Join BYJU'S Learning Program