The correct option is A 2
Fornumbertobedivisibleby12,itmustbedivisibleby3&4bothTomakeby4,so,last(b)digitis2or6.Tomakeitdivisibleby3,sumofdigitisdivisibleby3.So,leastvalueofais8+7+a+2+7+9+3+1+b=37+a+bIfb=2,then,a=3fordivisibleby3butifb=6thena=2fordivisibleby3∴leastvalueofais2.