Question

Consider the number whose sum of digits is 27. Find the number that divides the given number without any remainder.

• A. $3$
• B. $9$
• C. $18$
• D. $1$

Answer 1

Answer: (A), (B), (D)

$1$

For the number whose sum of the digits is $27.$

$27$ is a multiple of $3,9$ and $27.$

$\therefore$ The given number is completely divisible by $3,9$ and $1$

For example, $999\to 9+9+9=27$
The number is completely divisible by $3,9$ and $1.$