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Question

Consider the op-amp circuit shown in the figure below.

The source Vi is a sinusoidal signal with input frequency of 50 Hz and rms value of 10 V. Then the magnitude of source current Ii is equal to

A
18.224 mA
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B
36.666 mA
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C
43.145 mA
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D
31.415 mA
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Solution

The correct option is D 31.415 mA

Applying KCL at inverting terminal.
V01/sC+VV0(s)1/sC=0[V+=V=Vi(s)]
V0(s)Vi(s)=(1+RCs)
The current Ii=Vi(s)V0(s)R
Ii=sRCR.Vi(s)=sCVi(s)
Ii=jωCVi(s)
|Ii|=2πf×10×106×10
=10π×103=31.415 mA

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