Consider the opamp configuration shown in figure below-If the value of circuit parameters are L-1 - H- C-1 - F- R1-R2-R3-1 - then the overall voltage gain -Vout-Vin- of circuit will be-

H_1(s)=V_01V_i=1+R_1sL=1+1sL=1+1s×10^ 6 H_2(s)=V_0V_01= R_3R_2Cs+1Cs= sR_3C1+sR_2C = Cs1+Cs= 11+1Cs H(s)=H_1(s)H_2(s)=(1+1s×10^ 6)( s×1×10^ 61+s×10^ 6)= 1 ...

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Standard XII

Physics

Impedance

Consider the ...

Question

Consider the opamp configuration shown in figure below,

If the value of circuit parameters are $L = 1 μ H, C = 1 μ F, R_{1} = R_{2} = R_{3} = 1 Ω$ , then the overall voltage gain | $V_{o u t} / V_{i n}$ | of circuit will be______.
1

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Solution

The correct option is A 1

$H_{1} (s) = \frac{V_{01}}{V_{i}} = 1 + \frac{R_{1}}{s L} = 1 + \frac{1}{s L} = 1 + \frac{1}{s \times 10^{- 6}}$

$H_{2} (s) = \frac{V_{0}}{V_{01}} = \frac{- R_{3}}{\frac{R_{2} C s + 1}{C s}} = \frac{- s R_{3} C}{1 + s R_{2} C}$

$= \frac{- C s}{1 + C s} = \frac{- 1}{1 + \frac{1}{C s}}$

$H (s) = H_{1} (s) H_{2} (s) = (1 + \frac{1}{s \times 10^{- 6}}) (\frac{- s \times 1 \times 10^{- 6}}{1 + s \times 10^{- 6}}) = - 1$

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Consider the opamp configuration shown in figure below, If the value of circuit parameters are L=1μH,C=1μF,R1=R2=R3=1Ω, then the overall voltage gain |Vout/Vin| of circuit will be______.1

The correct option is A 1 H1(s)=V01Vi=1+R1sL=1+1sL=1+1s×10−6 H2(s)=V0V01=−R3R2Cs+1Cs=−sR3C1+sR2C =−Cs1+Cs=−11+1Cs H(s)=H1(s)H2(s)=(1+1s×10−6)(−s×1×10−61+s×10−6)=−1

Consider the opamp configuration shown in figure below,

If the value of circuit parameters are $L = 1 μ H, C = 1 μ F, R_{1} = R_{2} = R_{3} = 1 Ω$ , then the overall voltage gain | $V_{o u t} / V_{i n}$ | of circuit will be______.
1