Consider the parabola x2+4y=0. Let (a,b) be any fixed point inside the parabola and let 'S' be the focus of the parabola. Then the minimum value of SQ+PQ as point Q moves on the parabola is
A
|1-a|
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B
|ab|+1
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C
√a2+b2
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D
1-b
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Solution
The correct option is D 1-b Let foot of perpendicular from Q to the directrix be N ⇒ SQ+PQ=QN+PQ is minimum if P,Q and N are collinear So minimum value of SQ+PQ = PN = 1-b.