Consider the periodic signal xt-1-0-5cos 40- tcos 200- twhere t is in seconds- Its fundamental frequency in Hz is

Given signal is x(t)=cos 200π t+12(cos 40π t×cos 200π t) nbsp; nbsp; nbsp; nbsp; =cos 200π t+14cos 240π t+14cos 160π t G.C.D. of frequency compone ...

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Standard XII

Physics

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Consider the ...

Question

Consider the periodic signal
$x (t) = (1 + 0.5 cos 40 π t) cos 200 π t$
where t is in seconds. Its fundamental frequency in Hz is

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Solution

The correct option is A 20
$Given signal is$
$x (t) = cos 200 π t + \frac{1}{2} (cos 40 π t \times cos 200 π t)$

$= cos 200 π t + \frac{1}{4} cos 240 π t + \frac{1}{4} cos 160 π t$

$G.C.D. of frequency components$ ,
$ω = 40 π$

$2 π f = 40 π$

$∴ f = 20 H z$

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Consider the periodic signal x(t)=(1+0.5cos40πt)cos200πt where t is in seconds. Its fundamental frequency in Hz is

The correct option is A 20Given signal is x(t)=cos200πt+12(cos40πt×cos200πt) =cos200πt+14cos240πt+14cos160πt G.C.D. of frequency components, ω=40π 2πf=40π ∴f=20Hz

Consider the periodic signal
$x (t) = (1 + 0.5 cos 40 π t) cos 200 π t$
where t is in seconds. Its fundamental frequency in Hz is

The correct option is A 20
$Given signal is$
$x (t) = cos 200 π t + \frac{1}{2} (cos 40 π t \times cos 200 π t)$

$= cos 200 π t + \frac{1}{4} cos 240 π t + \frac{1}{4} cos 160 π t$

$G.C.D. of frequency components$ ,
$ω = 40 π$

$2 π f = 40 π$

$∴ f = 20 H z$