Question

Consider the points $P(2,-4);Q(4,-2)$ and $R=(7,1)$. The points $P,Q,R$.

• A. Form an equilateral triangle
• B. Form a right angled triangle triangle
• C. Form an isosceles triangle which is not equilateral
• D. are collinear

Answer 1

The correct option is D are collinear

$P(2,-4)Q(4,-2)R(7,1)$

Check for option A

$PQ=2\sqrt{2}$

$QR=3\sqrt{2}$

$RP=5\sqrt{2}$

Not an equilateral $\Delta$

Now, equation of line of PQ

$(x-4)\left(1\right)=y+2$

$x-y=6$

Satisfies point R

Hence PQR are collinear point.