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Question

Consider the polynomial x3+2x+15−72x2−x6.
The constant term is:

A
17
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B
15
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C
12
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D
13
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Solution

The correct option is A 15
x3+2x+1572x2x6
=x3+2x+1572x2x6
=x6+x357x22+2x5+15
So, the constant term= 15

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