Consider the quadratic equation (c−5)x2−2cx+(c−4)=0, c≠5. Let S be the set of all integral values of c for which one root of the equation lies in the interval (0,2) and its other root lies in the interval (2,3). Then the number of elements in S is?
A
11
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B
18
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C
10
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D
12
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Solution
The correct option is B11 Let f(x)=(c−5)c2−2cx+c−4 ∴f(0)f(2)<0 .................(1) & f(2)f(3)<0 ...........................(2) from (1) & (2) (c−4)(c−24)<0 & (c−24)(4c−49)<0 ⇒494<c<24 ∴s={13,14,15,.....23} Number of elements in set S=11.